JEE Advanced · Chemistry · 9. Redox Reactions
Reaction of \(\mathrm{Br}_2\) with \(\mathrm{Na}_2 \mathrm{CO}_3\) in aqueous solution gives sodium bromide and sodium bromate with evolution of \(\mathrm{CO}_2\) gas. The number of sodium bromide molecules involved in the balanced chemical equation is
- A 5
- B 10
- C 15
- D 20
Answer & Solution
Correct Answer
(A) 5
Step-by-step Solution
Detailed explanation
\(\mathrm{Br}_2\) is disproportionated in basic medium as
\(3 \mathrm{Br}_2+3 \mathrm{Na}_2 \mathrm{CO}_3 \longrightarrow 5 \mathrm{NaBr}+\mathrm{NaBrO}_3\) \(+~3 \mathrm{CO}_2\)
\(3 \mathrm{Br}_2+3 \mathrm{Na}_2 \mathrm{CO}_3 \longrightarrow 5 \mathrm{NaBr}+\mathrm{NaBrO}_3\) \(+~3 \mathrm{CO}_2\)
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