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JEE Advanced · Mathematics · 3. Complex Numbers

For a complex number z, let Rez denote the real part of z. Let S be the set of all complex numbers z satisfying z4-|z|4=4iz2, where i=-1. Then the minimum possible value of z1-z22, where z1,z2S with Rez1>0 and Rez2<0, is _______

  1. A 2
  2. B 4
  3. C 6
  4. D 8
Verified Solution

Answer & Solution

Correct Answer

(D) 8

Step-by-step Solution

Detailed explanation

z4-|z|4=4iz2z4-zz¯2=4iz2
  z2z2-z¯2=4iz2    z2-z¯2=4i
  z+z¯z-z¯=4i
  z+z¯2z-z¯2i=1    xy=1
for z1 & z2    x1y1=1 and  x2y2=1
x1 & x2 are of opposite sign, similarly 
y1 & y2 are of opposite sign
  x1>0,y1>0, x2<0,y2<0
Now   z1-z22=x1-x22+y1-y22
=x12+x22+y12+y22-2x1x2-2y1y2
\(=x_1^2+x_2^2+y_1^2+y_2^2+x_1\left(-x_2\right)+x_1\) \(\left(-x_2\right)+y_1\left(-y_2\right)+y_1\left(-y_2\right) \)
\( \geq 8(x_1^2 \cdot x_2^2 \cdot y_1^2 \cdot y_2^2 \cdot x_1\left(-x_2\right) \cdot x_1\left(-x_2\right) \cdot\) \(y_1\left(-y_2\right) \cdot y_1\left(-y_2\right)\)\(^{1 / 8}\)
8x1y14x2y241/8
8.
From JEE Advanced
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