JEE Advanced · Physics · 21. EMI
The figure shows certain wire segments joined together to form a coplanar loop. The loop is placed in a perpendicular
magnetic field in the direction going into the plane of the figure. The magnitude of the field increases with time. \(I_1\) and \(I_2\) are the currents in the segments \(a b\) and \(c d\). Then,

- A \(I_1>I_2\)
- B \(I_1 < I_2\)
- C \(I_1\) is in the direction ba and \(I_2\) is in the direction \(c d\)
- D \(I_1\) is in the direction \(a b\) and \(I_2\) is in the direction \(d c\)
Answer & Solution
Correct Answer
(D) \(I_1\) is in the direction \(a b\) and \(I_2\) is in the direction \(d c\)
Step-by-step Solution
Detailed explanation
Cross \(\otimes\) magnetic field passing from the closed loop is increasing. Therefore, from Lenz's law induced current will product \(\operatorname{dot} \odot\) magnetic field. Hence, induced current is anticlockwise.
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