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JEE Advanced · Chemistry · 17. Electrochemistry

In an electrochemicalcell, dichromate ions in aqueous acidic medium are reduced to \(\mathrm{Cr}^{3+}\). The current (in amperes) that flows through the cell for 48.25 minutes to produce 1 mole of \(\mathrm{Cr}^{3+}\) is _____ .
Use: 1 Faraday \(=96500 \mathrm{C} \mathrm{mol}^{-1}\)

  1. A 100
  2. B 200
  3. C 300
  4. D 400
Verified Solution

Answer & Solution

Correct Answer

(A) 100

Step-by-step Solution

Detailed explanation

For reduction of dichromate, balanced reaction is :
\(\mathrm{Cr}_2 \mathrm{O}_7^{-2}(\mathrm{aq})+6 \mathrm{e}^{-}+14 \mathrm{H}^{+}(\mathrm{aq}) \rightarrow 2 \mathrm{Cr}^{3+}(\mathrm{aq})\) \(+~7 \mathrm{H}_2 \mathrm{O}(\mathrm{l})\)
\(\qquad \qquad \qquad3 Mole\) \(\qquad \qquad \qquad \qquad 1 Mole\)
Number of Farads required \(=3 \mathrm{~mol}\)
Let current \(=\mathrm{I}\) amperes
\(\begin{aligned}
& \Rightarrow \frac{I \times 48.25 \times 60}{96500}=3 \\
& I=100 \mathrm{~A}
\end{aligned}\)
From JEE Advanced
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