AP EAMCET · PHYSICS · Current Electricity
A cell of emf 1.2 V and internal resistance \(2 \Omega\) is connected in parallel to another cell of emf 1.5 V and internal resistance \(1 \Omega\). If the like poles of the cells are connected together, the emf of the combination of the two cells is
- A 0.8 V
- B 3.9 V
- C 2.7 V
- D 1.4 V
Answer & Solution
Correct Answer
(D) 1.4 V
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { } \mathrm{E}_1=1.2 \mathrm{~V}, \mathrm{r}_1=2 \Omega, \mathrm{E}_2=1.5 \mathrm{~V}, \mathrm{r}_2=1 \Omega \\ & \mathrm{E}_{\text {eq }}=\frac{\frac{\mathrm{E}_1}{\mathrm{r}_1}+\frac{\mathrm{E}_2}{\mathrm{r}_2}}{\frac{1}{\mathrm{r}_1}+\frac{1}{\mathrm{r}…
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