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AP EAMCET · PHYSICS · Thermal Properties of Matter

A block of steel of mass \(2 \mathrm{~kg}\) slides down a rough inclined plane of inclination of \(\sin ^{-1}\left(\frac{3}{5}\right)\) at a constant speed. The temperature of the block as it slides through \(80 \mathrm{~cm}\), assuming that the mechanical energy lost is used to increase the temperature of the block is nearly
(Specific heat capacity of steel \(=420 \mathrm{Jkg}^{-1} \mathrm{~K}^{-1}\) and Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )

  1. A \(0.0190^{\circ} \mathrm{C}\)
  2. B \(0.0114^{\circ} \mathrm{C}\)
  3. C \(0.0152^{\circ} \mathrm{C}\)
  4. D \(0.0952^{\circ} \mathrm{C}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(0.0152^{\circ} \mathrm{C}\)

Step-by-step Solution

Detailed explanation

Work done due to sliding down the block = heat gain by block of steel…