AP EAMCET · Maths · Straight Lines
Suppose the vertices of a triangle are given by \(\mathrm{A}(0,3)\), \(\mathrm{B}(-2,0)\) and \(\mathrm{C}(6,1)\). For \((\alpha, \alpha+1)\) to lie inside the triangle, \(\alpha\) should lie in the interval
- A \(\left(\frac{-6}{7}, 4\right)\)
- B \(\left(\frac{4}{5}, 4\right)\)
- C \(\left(-\infty, \frac{-6}{7}\right) \cup(4, \infty)\)
- D \(\left(\frac{-6}{7}, \frac{3}{2}\right)\)
Answer & Solution
Correct Answer
(D) \(\left(\frac{-6}{7}, \frac{3}{2}\right)\)
Step-by-step Solution
Detailed explanation
Given points \(\mathrm{A}(0,3)\) \(\mathrm{B}(-2,0)\) and \(\mathrm{C}(6,1)\) as vertices of triangle \(\mathrm{ABC}\) how Line \(A C=x+3 y=9\)...(i) and \(\mathrm{BC}=\mathrm{x}-8 \mathrm{y}=-2\)...(ii) for \((\alpha, \alpha+1)\) lies in side te triangle \(\mathrm{ABC}\) Let…
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