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AP EAMCET · PHYSICS · Laws of Motion

A lorry is moving on a smooth circular path of radius 50 \(\mathrm{m}\) with a velocity of \(20 \mathrm{~ms}^{-1}\). Then the banking angle of the road is
(Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )

  1. A \(\tan ^{-1} \frac{5}{4}\)
  2. B \(\tan ^{-1} \frac{4}{5}\)
  3. C \(\tan ^{-1} \frac{2}{5}\)
  4. D \(\tan ^{-1} \frac{5}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\tan ^{-1} \frac{4}{5}\)

Step-by-step Solution

Detailed explanation

Radius of circular path, \(R=50 \mathrm{~m}\) Velocity, \(V=20 \mathrm{~m} / \mathrm{s}\) Banking angle of the road, \(\tan \theta=\frac{V^2}{R g}\) \(\theta=\tan ^{-1}\left(\frac{20^2}{50 \times 10}\right)=\tan ^{-1}\left(\frac{4}{5}\right)\)
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