AP EAMCET · PHYSICS · Mechanical Properties of Fluids
The terminal velocity \(v\) of a spherical ball of lead of radius \(R\) falling through a viscous liquid varies with \(R\) such that
- A \(\frac{v}{R}=\) constant
- B \(v R=\) constant
- C \(v=\) constant
- D \(\frac{v}{R^2}=\) constant
Answer & Solution
Correct Answer
(D) \(\frac{v}{R^2}=\) constant
Step-by-step Solution
Detailed explanation
Terminal velocity of spherical ball falling through viscous liquid is given as \(v=\frac{2}{9} \times \frac{R^2(\rho-\sigma) g}{\eta}\) ...(i) where, \(R=\) radius of ball, \(\rho=\) density of ball, \(\sigma=\) density of liquid and \(\eta=\) coefficient of viscosity. From Eq.…
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