AP EAMCET · PHYSICS · Alternating Current
The resonant frequency of an LC circuit is \(f_0\). If a dielectric slab of constant 16 is inserted completely between the plates of the capacitor, then the resonant frequency is
- A \(\frac{f_o}{2}\)
- B \(2 \mathrm{f}_{\mathrm{o}}\)
- C \(\frac{\mathrm{f}_{\mathrm{o}}}{4}\)
- D \(4 \mathrm{f}_{\mathrm{o}}\)
Answer & Solution
Correct Answer
(C) \(\frac{\mathrm{f}_{\mathrm{o}}}{4}\)
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