AP EAMCET · PHYSICS · Magnetic Properties of Matter
The domain in ferromagnetic material is in the form of a cube of side \(2 \mu \mathrm{~m}\). Number of atoms in that domain is \(9 \times 10^{10}\) and each atom has a dipole movement of \(9 \times 10^{-24} \mathrm{Am}^2\). The magnetisation of the domain is (approximately),
- A \(10 \times 10^4 \mathrm{Am}^{-1}\)
- B \(8 \times 10^4 \mathrm{Am}^{-1}\)
- C \(12 \times 10^4 \mathrm{Am}^{-1}\)
- D \(9 \times 10^4 \mathrm{Am}^{-1}\)
Answer & Solution
Correct Answer
(A) \(10 \times 10^4 \mathrm{Am}^{-1}\)
Step-by-step Solution
Detailed explanation
Volume of the domain, \(\mathrm{V}=\left(2 \times 10^{-6}\right)^3=8 \times 10^{-18} \mathrm{~m}^3\)…
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