AP EAMCET · PHYSICS · Mechanical Properties of Solids
If the pressure on a body is increased from 200 kPa to 250 kPa, the volume of the body decreases by \(0.25 \%\). The compressibility of the material of the body is (in \(\mathrm{m}^2 \mathrm{~N}^{-1}\) )
- A \(2 \times 10^7\)
- B \(2 \times 10^{-7}\)
- C \(5 \times 10^8\)
- D \(5 \times 10^{-8}\)
Answer & Solution
Correct Answer
(D) \(5 \times 10^{-8}\)
Step-by-step Solution
Detailed explanation
\( \Delta P = 250 \text{ kPa} - 200 \text{ kPa} = 50 \text{ kPa} = 50 \times 10^3 \text{ Pa} \) \( \frac{\Delta V}{V} = -0.25\% = -0.0025 \) \( \kappa = -\frac{\Delta V / V}{\Delta P} \) \( \kappa = -\frac{-0.0025}{50 \times 10^3 \text{ Pa}} \)…
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