AP EAMCET · Maths · Hyperbola
The equation of a tangent to the hyperbola \(16 x^2-25 y^2-96 x+100 y-356=0\) which makes an angle \(45^{\circ}\) with its transverse axis is
- A \(x-y+2=0\)
- B \(x-y+4=0\)
- C \(x+y+2=0\)
- D \(x+y+4=0\)
Answer & Solution
Correct Answer
(A) \(x-y+2=0\)
Step-by-step Solution
Detailed explanation
Given equation of hyperbola \(\begin{aligned} & 16 x^2-25 y^2-96 x+100 y-356=0 \\ & \Rightarrow \quad \frac{(x-3)^2}{25}-\frac{(y-2)^2}{16}=1 \quad \ldots (i) \end{aligned}\) Now equation of tangent to the hyperbola (i) having slope ' 1 ' is…
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