AP EAMCET · Maths · Circle
The radius of the larger circle lying in the first quadrant and touching the line \(4 x+3 y-12=0\) and the co-ordinate axes, is
- A \(5\)
- B \(6\)
- C \(7\)
- D \(8\)
Answer & Solution
Correct Answer
(B) \(6\)
Step-by-step Solution
Detailed explanation
Let the equation of the circle is \[ x^2+y^2+2 g x+2 f y+c=0 \] This circle touch the coordinate axes and lying in the first quadrant, then \[ \begin{aligned} g^2-c & =0 \text { and } f^2-c=0 \\ g & = \pm \sqrt{c}, f= \pm \sqrt{c} \end{aligned} \] circle lies in first quadrant…
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