AP EAMCET · Maths · Complex Number
If \((1+x)^n=p_0+p_1 x+p_2 x^2+\ldots+p_n x^n\), then \(p_0+p_3+p_6+\ldots=\)
- A \(\frac{1}{3}\left[2^{n-1}+\cos \frac{n \pi}{3}\right]\)
- B \(\frac{2}{3}\left[2^{n-1}+\cos \frac{n \pi}{3}\right]\)
- C \(\frac{1}{3}\left[2^{n-2}+\sin \frac{n \pi}{3}\right]\)
- D \(\frac{2}{3}\left[2^{n-2}+\sin \frac{n \pi}{6}\right]\)
Answer & Solution
Correct Answer
(B) \(\frac{2}{3}\left[2^{n-1}+\cos \frac{n \pi}{3}\right]\)
Step-by-step Solution
Detailed explanation
\(3(p_0+p_3+p_6+\ldots) = (1+1)^n + (1+\omega)^n + (1+\omega^2)^n\) Where \(\omega = e^{i2\pi/3}\). \(1+\omega = e^{i\pi/3}\) and \(1+\omega^2 = e^{-i\pi/3}\) \(3S = 2^n + (e^{i\pi/3})^n + (e^{-i\pi/3})^n\) \(3S = 2^n + e^{in\pi/3} + e^{-in\pi/3}\)…
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