AP EAMCET · Maths · Straight Lines
The transformed equation of \(2 x^2+3 y^2-z^2-8 x+18 y\) \(+2 z+9=0\) when the axes are translated to the point \((2,-3,1)\) is
- A \(2 x^2+3 y^2-z^2=25\)
- B \(2 x^2+3 y^2+z^2=25\)
- C \(2 x^2-3 y^2-z^2=25\)
- D \(2 x^2+3 y^2-z^2=50\)
Answer & Solution
Correct Answer
(A) \(2 x^2+3 y^2-z^2=25\)
Step-by-step Solution
Detailed explanation
Since the axes are translated by \((2,-3,1)\) \(\begin{aligned} & \text { Let } x-2=X \Rightarrow x=X+2 \\ & y+3=Y \Rightarrow y=Y-3 \\ & z-1=Z \Rightarrow z=Z+1\end{aligned}\) \(\because 2 x^2+3 y^2-z^2-8 x+18 y+2 z+9=0\)…
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