AP EAMCET · Maths · Permutation Combination
\(\frac{10001 \times 100 !}{2 \times 1 !+5 \times 2 !+10 \times 3 !+\ldots+10001 \times 100 !}=\)
- A \(\frac{1001}{1100}\)
- B \(\frac{10001}{10100}\)
- C \(\frac{101}{110}\)
- D \(\frac{100001}{101000}\)
Answer & Solution
Correct Answer
(B) \(\frac{10001}{10100}\)
Step-by-step Solution
Detailed explanation
Here, general term of denominator is…
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