AP EAMCET · PHYSICS · Work Power Energy
A boy weighing 50 kg finished long jump at a distance of 8 m . Considering that he moved along a parabolic path and his angle of jump is \(45^{\circ}\), his initial \(K E\) is
- A 960 J
- B 1560 J
- C 2460 J
- D 1960 J
Answer & Solution
Correct Answer
(D) 1960 J
Step-by-step Solution
Detailed explanation
\(\mathrm{R}=8 \mathrm{~m}, \theta=45^{\circ}\) \(\begin{aligned} & \therefore \quad R=\frac{u^2 \sin 2 \theta}{g}=\frac{u^2 \sin 90^{\circ}}{g}=\frac{u^2}{9.8} \\ & \therefore \quad u^2=9.8 R=9.8 \times 8=78.4 \end{aligned}\) \(\therefore \quad\) Initial K.E. of the man,…
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