AP EAMCET · Maths · Vector Algebra
In a regular hexagon \(A B C D E F\), \(\mathbf{A D}+\mathbf{E B}+\mathbf{F C}=(\beta \lambda-8) \mathbf{A B}\). Then \(\lambda=\)
- A 3
- B 4
- C 5
- D 6
Answer & Solution
Correct Answer
(B) 4
Step-by-step Solution
Detailed explanation
Since, \(\mathbf{A D} \| \mathbf{B C}\) and \(\mathbf{A D}=2 \mathbf{B C}\) \(\begin{gathered} \mathbf{E B} \| \mathbf{F A} \text { and } \mathbf{E B}=2 \mathbf{F A} \\ \mathbf{F C} \| \mathbf{A B} \text { and } \mathbf{F C}=2 \mathbf{A B} \end{gathered}\)…
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