जब किसी प्रकाशसंवेदी सतह पर \(v\) आवृत्ति का एकवर्णीय प्रकाश आपतित किया जाता है तो प्रकाश धारा के लिये निरोधी विभव \(- V _{0} / 2\) प्राप्त होता है। जब सतह पर \(v / 2\) आवृत्ति का एकवर्णीय प्रकाश आपतित किया जाता है तो निरोधी विभव का मान \(- V _{0}\) होता है। प्रकाश उत्सर्जन के लिये दैहली आवृत्ति होगी ।

A \(\frac {5v}{3}\)
B \(\frac {4}{3}\,v\)
C \(2\,v\)
D \(\frac {3v}{2}\)

Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac {3v}{2}\)

Step-by-step Solution

Detailed explanation

\({\text{e}}{{\text{V}}_{\text{s}}} = {\text{hv}} - \phi \) \(\left\{ {\frac{{ - e{V_0}}}{2} = hv - \phi } \right\} \times 2\) ..... \((1)\) \( - e{V_0} = \frac{{hv}}{2} - \phi \) ..... \((2)\) \(0 = 2hv - 2\phi - \frac{{hv}}{2} + \phi \) \(\phi = \frac{{3hv}}{2}\)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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