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JEE Mains · Maths · STD 11 - 4.1 complex nubers

यदि \(\mathrm{z}=\frac{1}{2}-2 \mathrm{i}\), के लिए \(|\mathrm{z}+1|=\alpha \mathrm{z}+\beta(1+\mathrm{i}), \mathrm{i}=\sqrt{-1} \)है जहाँ \( \alpha, \beta \in \mathrm{R} \text {, }\) है तो \(\alpha+\beta\) = ...........

  1. A \(-4\)
  2. B \(3\)
  3. C \(2\)
  4. D \(-1\)
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Correct Answer

(B) \(3\)

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Detailed explanation

\( \mathrm{z}=\frac{1}{2}-2 \mathrm{i} \) \( |\mathrm{z}+1|=\alpha \mathrm{z}+\beta(1+\mathrm{i}) \) \( \left|\frac{3}{2}-2 \mathrm{i}\right|=\frac{\alpha}{2}-2 \alpha \mathrm{i}+\beta+\beta \mathrm{i} \)…
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