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JEE Mains · Maths · STD 12 - 9. differential equations

मान लीजिए कि अवकल समीकरण \(x\left(x^2+e^x\right) d y+\left(e^x(x-2) y-x^3\right) d x=0, x \gt 0\) का हल वक्र \(y=y(x)\) है, जो बिंदु \((1,0)\) से गुजरता है। तो \(y(2)\) = ___

  1. A \(\frac{4}{4-\mathrm{e}^2}\)
  2. B \(\frac{2}{2+\mathrm{e}^2}\)
  3. C \(\frac{2}{2-\mathrm{e}^2}\)
  4. D \(\frac{4}{4+\mathrm{e}^2}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{4}{4+\mathrm{e}^2}\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & x\left(x^2+e^x\right) d y+\left(e^x(x-2) y-x^3\right) d x=0 \\ & x\left(x^2+e^x\right) \frac{d y}{d x}+e^x(x-2) y=x^3 \\ & \frac{d y}{d x}+\frac{e^x(x-2)}{x\left(x^2+e^x\right)} y=\frac{x^2}{x^2+e^x} \\ & \text { I.F. }=e^{\int…

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