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JEE Mains · Maths · STD 11 - 7. binomial theoram

यदि संख्या \(\frac{2^{403}}{15}\) का भिन्नात्मक भाग (fractional part) \(\frac{ k }{15}\) है, तो \(k\) बराबर हैं-

  1. A \(6\)
  2. B \(8\)
  3. C \(4\)
  4. D \(14\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(8\)

Step-by-step Solution

Detailed explanation

\(\frac{2^{403}}{15}=\frac{2^{3} \cdot 2^{400}}{15}=\frac{8 \cdot(1+15)^{100}}{15}\) \( = \frac{{8\left( {^{100}{{\text{C}}_0}{ + ^{100}}{{\text{C}}_1}(15){ + ^{100}}{{\text{C}}_2}{{(15)}^2} + \ldots \ldots } \right)}}{{15}}\)…
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