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JEE Mains · Maths · STD 11 - 8. sequence and series

यदि \(\left\{ a _{ i }\right\}_{ i =1}^{ n }\) (जहाँ \(n\) सम पूर्णांक है) समान्तर श्रेढ़ी है जिसका सार्वअन्तर \(1\) तथा \(\sum \limits_{ i =1}^{ n } a _{ i }=192\), \(\sum \limits_{ i =1}^{ n / 2} a _{2 i }=120\) है, तो \(n\) बराबर है:

  1. A \(48\)
  2. B \(96\)
  3. C \(92\)
  4. D \(104\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(96\)

Step-by-step Solution

Detailed explanation

\(\sum \limits_{ i =1}^{ n } a _{ i }=\frac{ n }{2}\left\{2 a _{1}+( n +1)\right\}=192\) \(\Rightarrow 2 a _{1}+( n -1)=\frac{384}{ n } \ldots-(1)\) \(\sum \limits_{ i =1}^{ n / 2} a _{2 i }=\frac{ n }{4}\left[2 a _{1}+2+\left(\frac{ n }{2}-1\right) 2\right]=120\)…
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