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JEE Mains · Maths · STD 12 - 9. differential equations

यदि अवकलन समीकरण \(\frac{d y}{d x}=\frac{x+y-2}{x-y}\) का हल वक्र, जो बिंदु \((2,1)\) से होकर जाता है, \(\tan ^{-1}\left(\frac{y-1}{x-1}\right)-\frac{1}{\beta} \log _e\left(\alpha+\left(\frac{y-1}{x-1}\right)^2\right)=\log _e|x-1|\) है, तो \(5 \beta+\alpha\) = ...........

  1. A \(12\)
  2. B \(11\)
  3. C \(14\)
  4. D \(0\)
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Answer & Solution

Correct Answer

(B) \(11\)

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Detailed explanation

\( \frac{d y}{d x}=\frac{x+y-2}{x-y} \) \( \mathrm{x}=\mathrm{X}+\mathrm{h}, \mathrm{y}=\mathrm{Y}+\mathrm{k} \) \(4 \frac{d Y}{d X}=\frac{X+Y}{X-Y} \) \(\mathrm{h}+\mathrm{k}-2=0 \) \(\mathrm{~h}-\mathrm{k}=0\) \( \mathrm{Y}=\mathrm{vX} \)…
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