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JEE Mains · Maths · STD 11 - 4.1 complex nubers

यदि \(\frac{3+ i \sin \theta}{4- i \cos \theta}, \theta \in[0,2 \pi]\), एक वास्तविक संख्या है, तो \(\sin \theta+i \cos \theta\) का एक कोणांक (argument) है

  1. A \(-\tan ^{-1}\left(\frac{3}{4}\right)\)
  2. B \(\tan ^{-1}\left(\frac{4}{3}\right)\)
  3. C \(\pi-\tan ^{-1}\left(\frac{4}{3}\right)\)
  4. D \(\pi-\tan ^{-1}\left(\frac{3}{4}\right)\)
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Answer & Solution

Correct Answer

(C) \(\pi-\tan ^{-1}\left(\frac{4}{3}\right)\)

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Detailed explanation

\(\frac{3+i \sin \theta}{4-i \cos \theta}\) is a real number \(\Rightarrow 3 \cos \theta+4 \sin \theta=0\) \(\Rightarrow \tan \theta=\frac{-3}{4}\) argument of \(\sin \theta+i \cos \theta=\pi-\tan ^{-1} \frac{4}{3}\)
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