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JEE Mains · Maths · STD 12 - 2. inverse trigonometric function

यदि \(\alpha=\cos ^{-1}\left(\frac{3}{5}\right), \beta=\tan ^{-1}\left(\frac{1}{3}\right)\) है, जहाँ \(0<\alpha, \beta<\frac{\pi}{2}\) तो \(\alpha-\beta\) बराबर है

  1. A \({\sin ^{ - 1}}\,\left( {\frac{9}{{5\sqrt {10} }}} \right)\)
  2. B \({\cos ^{ - 1}}\,\left( {\frac{9}{{5\sqrt {10} }}} \right)\)
  3. C \({\tan ^{ - 1}}\,\left( {\frac{9}{{5\sqrt {10} }}} \right)\)
  4. D \({\tan ^{ - 1}}\,\left( {\frac{9}{{14}}} \right)\)
Verified Solution

Answer & Solution

Correct Answer

(A) \({\sin ^{ - 1}}\,\left( {\frac{9}{{5\sqrt {10} }}} \right)\)

Step-by-step Solution

Detailed explanation

\(\cos \alpha = \frac{3}{5},\tan \beta \frac{1}{3}\) \( \Rightarrow \tan \alpha = \frac{4}{3}\) \( \Rightarrow \tan \left( {\alpha - \beta } \right) = \frac{{\frac{4}{3} - \frac{1}{3}}}{{1 + \frac{4}{3},\frac{1}{3}}} = \frac{9}{{13}}\)…
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