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JEE Mains · Maths · STD 12 - 2. inverse trigonometric function

\(\cot \left(\sum_{n=1}^{19} \cot ^{-1}\left(1+\sum_{p=1}^{n} 2 p\right)\right)\) का मान होगा

  1. A \(\frac{21}{19}\)
  2. B \(\frac{19}{21}\)
  3. C \(\frac{22}{23}\)
  4. D \(\frac{23}{22}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{21}{19}\)

Step-by-step Solution

Detailed explanation

\(\cot \left[ {\sum\limits_{n = 1}^{19} {{{\cot }^{ - 1}}\left( {1 + \sum\limits_{p = 1}^n {2q} } \right)} } \right]\) \( = \cot \left[ {\sum\limits_{n = 1}^{19} {{{\cot }^{ - 1}}\left( {1 + {n^2} + n} \right)} } \right]\)…
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