JEE Mains · Maths · STD 12 - 2. inverse trigonometric function
The value of \(\cot \left( {\sum\limits_{n = 1}^{19} {{{\cot }^{ - 1}}\left( {1 + \sum\limits_{p = 1}^n {2p} } \right)} } \right)\) is
- A \(\frac{21}{19}\)
- B \(\frac{19}{21}\)
- C \(\frac{22}{23}\)
- D \(\frac{23}{22}\)
Answer & Solution
Correct Answer
(A) \(\frac{21}{19}\)
Step-by-step Solution
Detailed explanation
\(\cot \left[ {\sum\limits_{n = 1}^{19} {{{\cot }^{ - 1}}\left( {1 + \sum\limits_{p = 1}^n {2q} } \right)} } \right]\) \( = \cot \left[ {\sum\limits_{n = 1}^{19} {{{\cot }^{ - 1}}\left( {1 + {n^2} + n} \right)} } \right]\)…
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