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JEE Mains · Maths · STD 12 - 9. differential equations

माना \(y=y(x)\) अवकल समीकरण \(\frac{d y}{d x}+\frac{2 x}{\left(1+x^2\right)^2} y=x e^{\frac{1}{\left(1+x^2\right)}} ; y(0)=0\) का हल है। तब वक्र \(f(\mathrm{x})=\mathrm{y}(\mathrm{x}) \mathrm{e}^{-\frac{1}{\left(1+\mathrm{x}^2\right)}}\) और रेखा \(\mathrm{y}-\mathrm{x}=4\) द्वारा परिबद्ध क्षेत्रफल ........... है।

  1. A \(62\)
  2. B \(18\)
  3. C \(35\)
  4. D \(16\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(18\)

Step-by-step Solution

Detailed explanation

\( \text { IF }=e^{\int \frac{2 x}{\left(1+x^2\right)^2} d x}=e^{\frac{-1}{1+x^2}} \) \( y \cdot e^{\frac{-1}{1+x^2}}=\int x \cdot e^{\frac{1}{1+x^2}} \cdot e^{\frac{-1}{1+x^2} d x} \) \( y \cdot e^{\frac{-1}{1+x^2}}=\frac{x^2}{2}+c \) \( (0,0) \Rightarrow C=0 \)…
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