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JEE Mains · Maths · STD 12 - 6. Application of derivatives

माना \(\lambda\) का अधिकतम मान \(\lambda *\) है जहाँ \(f _\lambda( x )=4 \lambda x ^3-36 \lambda x ^2+36 x +48 \forall x \in R\) के लिये वर्धमान है, तो \(f _\lambda^*(1)+ f _\lambda^*(-1)\) बराबर होगा

  1. A \(36\)
  2. B \(48\)
  3. C \(64\)
  4. D \(72\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(72\)

Step-by-step Solution

Detailed explanation

\(f_{\lambda}(x)=4 \lambda x^{3}-36 \lambda x^{2}+36 x+48\) \(f_{\lambda}^{\prime}(x)=12 \lambda x^{2}-72 \lambda x+36\) \(f_{\lambda}^{\prime}(x)=12\left(\lambda x^{2}-6 \lambda x+3\right) \geq 0\) \(\therefore \lambda>0 \ and \,D \leq 0\)…
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