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JEE Mains · Maths · STD 12 - 9. differential equations

माना एक वक्र \(y = f ( x )\) बिंदु \((-2,2)\) से होकर जाता है तथा वक्र के किसी बिंदु \(( x , f ( x ))\) पर स्पर्शरेखा की प्रवणता \(f ( x )+ xf ^{\prime}( x )= x ^{2}\) द्वारा दी गई है।

  1. A \(x^{2}+2 x\, f(x)-12=0\)
  2. B \(x^{3}+x \,f(x)+12=0\)
  3. C \(x^{3}-3 x\, f(x)-4=0\)
  4. D \(x^{2}+2 x\, f(x)+4=0\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(x^{3}-3 x\, f(x)-4=0\)

Step-by-step Solution

Detailed explanation

\(y+\frac{x d y}{d x}=x^{2}(\text { given })\) \(\Rightarrow \frac{d y}{d x}+\frac{y}{x}=x\) \(\text { If }=e^{\int \frac{1}{x} d x}=x\) Solution of \(\mathrm{DE}\) \(\Rightarrow y \cdot x=\int x \cdot x d x\) \(\Rightarrow x y=\frac{x^{3}}{3}+\frac{c}{3}\) Passes through…
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