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JEE Mains · Maths · STD 12 - 10. vector algebra

माना एक सदिश \(\vec{a}\), सदिशों \(\overrightarrow{ b }=2 \hat{ i }+\hat{ j }+\hat{ k }\) तथा \(\overrightarrow{ c }=\hat{ i }-\hat{ j }+\hat{ k }\) के सहतलीय है। यदि \(\overrightarrow{ a }\), सदिश \(\overrightarrow{ d }=3 \hat{ i }+2 \hat{ j }+6 \hat{ k }\) पर लम्बवत है और \(|\overrightarrow{ a }|=\sqrt{10}\) है, तो \(\left[\begin{array}{lll}\vec{a} & \vec{b} & \vec{c}\end{array}\right]+\left[\begin{array}{lll}\vec{a} & b & \vec{d}\end{array}\right]+\left[\begin{array}{lll}\vec{a} & \vec{c} & \vec{d}\end{array}\right]\) का एक संभावित मान है -

  1. A \(-40\)
  2. B \(-42\)
  3. C \(-29\)
  4. D \(-38\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(-42\)

Step-by-step Solution

Detailed explanation

\(\vec{a}=\lambda \vec{b}+\mu \vec{c}=\hat{i}(2 \lambda+\mu)+\hat{j}(\lambda-\mu)+\hat{k}(\lambda+\mu)\) \(\vec{a} \cdot \vec{d}=0=3(2 \lambda+\mu)+2(\lambda-\mu)+6(\lambda+\mu)\) \(\Rightarrow 14 \lambda+7 \mu=0 \Rightarrow \mu=-2 \lambda\)…
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