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JEE Mains · Maths · STD 12 - 10. vector algebra

અહી સદીશ \(\vec{a}\) એ સદીશો \(\vec{b}=2 \hat{i}+\hat{j}+\hat{k}\) અને \(\vec{c}=\hat{i}-\hat{j}+\hat{k} .\) ને સમતલીય છે. જો \(\vec{a}\) એ  \(\vec{d}=3 \vec{i}+2 \hat{j}+6 \hat{k}\), અને \(|\vec{a}|=\sqrt{10} .\)  હોય તો  \([\overrightarrow{\mathrm{a}} \overrightarrow{\mathrm{b}} \overrightarrow{\mathrm{c}}]+[\overrightarrow{\mathrm{a}} \overrightarrow{\mathrm{b}} \vec{d}]+[\overrightarrow{\mathrm{a}} \vec{c} \vec{d}]\) ની શક્ય કિમંત મેળવો.

  1. A \(-40\)
  2. B \(-42\)
  3. C \(-29\)
  4. D \(-38\)
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Answer & Solution

Correct Answer

(B) \(-42\)

Step-by-step Solution

Detailed explanation

\(\vec{a}=\lambda \vec{b}+\mu \vec{c}=\hat{i}(2 \lambda+\mu)+\hat{j}(\lambda-\mu)+\hat{k}(\lambda+\mu)\) \(\vec{a} \cdot \vec{d}=0=3(2 \lambda+\mu)+2(\lambda-\mu)+6(\lambda+\mu)\) \(\Rightarrow 14 \lambda+7 \mu=0 \Rightarrow \mu=-2 \lambda\)…
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