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JEE Mains · Maths · STD 12 - 9. differential equations

माना अवकल समीकरण \(\frac{d y}{d x}=\frac{y}{x}\left(1+x y^2\left(1+\log _e x\right)\right), x>0, y(1)=3\) का हल \(\mathrm{y}=\mathrm{y}(\mathrm{x})\) है। तो \(\frac{\mathrm{y}^2(\mathrm{x})}{9}\) बराबर है। :

  1. A \(\frac{x^2}{5-2 x^3\left(2+\log _e x^3\right)}\)
  2. B \(\frac{x^2}{2 x^3\left(2+\log _e x^3\right)-3}\)
  3. C \(\frac{x^2}{3 x^3\left(1+\log _e x^2\right)-2}\)
  4. D \(\frac{x^2}{7-3 x^3\left(2+\log _e x^2\right)}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{x^2}{5-2 x^3\left(2+\log _e x^3\right)}\)

Step-by-step Solution

Detailed explanation

\(\frac{d y}{d x}-\frac{y}{x}=y^3\left(1+\log _e x\right)\) \(\frac{1}{y^3} \frac{d y}{d x}-\frac{1}{x y^2}=1+\log _e x\) \(\text { Let }-\frac{1}{y^2}=t \Rightarrow \frac{2}{y^3} \frac{d y}{d x}=\frac{d t}{d x}\)…
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