JEE Mains · Maths · STD 12 - 9. differential equations
Let \(y=y(x)\) be the solution curve of the differential equation \(\frac{d y}{d x}=\frac{y}{x}\left(1+x y^2\left(1+\log _e x\right)\right)\) \(x > 0, y(1)=3\). Then \(\frac{y^2(x)}{9}\) is equal to :
- A \(\frac{x^2}{5-2 x^3\left(2+\log _e x^3\right)}\)
- B \(\frac{x^2}{2 x^3\left(2+\log _e x^3\right)-3}\)
- C \(\frac{x^2}{3 x^3\left(1+\log _e x^2\right)-2}\)
- D \(\frac{x^2}{7-3 x^3\left(2+\log _e x^2\right)}\)
Answer & Solution
Correct Answer
(A) \(\frac{x^2}{5-2 x^3\left(2+\log _e x^3\right)}\)
Step-by-step Solution
Detailed explanation
\(\frac{d y}{d x}-\frac{y}{x}=y^3\left(1+\log _e x\right)\) \(\frac{1}{y^3} \frac{d y}{d x}-\frac{1}{x y^2}=1+\log _e x\) \(\text { Let }-\frac{1}{y^2}=t \Rightarrow \frac{2}{y^3} \frac{d y}{d x}=\frac{d t}{d x}\)…
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