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JEE Mains · Maths · STD 12 - 10. vector algebra

माना \(\vec{\alpha}=(\lambda-2) \vec{a}+\vec{b}\) तथा \(\vec{\beta}=(4 \lambda-2) \vec{a}+3 \vec{b}\) दो सदिश दिये गये है जहाँ सदिश \(\vec{a}\) तथा \(\vec{b}\) समरेखीय नहीं है। \(\lambda\) का वह मान, जिसके लिये सदिश \(\vec{\alpha}\) तथा \(\vec{\beta}\) समरेखीय हो, होगा

  1. A \(-4\)
  2. B \(-3\)
  3. C \(4\)
  4. D \(3\)
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Correct Answer

(A) \(-4\)

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Detailed explanation

\(\vec \alpha = (\lambda - 2)\overrightarrow {\rm{a}} + \overrightarrow {\rm{b}} \) \(\vec{\beta}=(4 \lambda-2) \overrightarrow{\mathrm{a}}+3 \overrightarrow{\mathrm{b}}\) \(\bar{\alpha}\) and \(\bar{\beta}\) are collinear…
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