JEE Mains · Maths · STD 12 - 10. vector algebra
Let \(\vec \alpha =(\lambda -2) \vec a + \vec b\) and \(\vec \beta = (4\lambda -2)\vec a + 3\vec b\) be two given vectors where \(\vec a\) and \(\vec b\) are non collinear. The value of \(\lambda \) for which vectors and \(\vec \alpha \) and \(\vec \beta \) are collinear, is
- A \(-4\)
- B \(-3\)
- C \(4\)
- D \(3\)
Answer & Solution
Correct Answer
(A) \(-4\)
Step-by-step Solution
Detailed explanation
\(\vec \alpha = (\lambda - 2)\overrightarrow {\rm{a}} + \overrightarrow {\rm{b}} \) \(\vec{\beta}=(4 \lambda-2) \overrightarrow{\mathrm{a}}+3 \overrightarrow{\mathrm{b}}\) \(\bar{\alpha}\) and \(\bar{\beta}\) are collinear…
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