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JEE Mains · Maths · STD 12 - 10. vector algebra

मान लीजिए एक एकांक सदिश जो \(2 \hat{i}+2 \hat{j}-\hat{k}\) के साथ \(60^{\circ}\) का कोण बनाता है और \(\hat{i}-\hat{k}\) के साथ \(45^{\circ}\) का कोण बनाता है, \(\overrightarrow{\mathrm{C}}\) है। तो \(\overrightarrow{\mathrm{C}}+\left(-\frac{1}{2} \hat{\mathrm{i}}+\frac{1}{3 \sqrt{2}} \hat{\mathrm{j}}-\frac{\sqrt{2}}{3} \hat{\mathrm{k}}\right)\) क्या है?

  1. A \(-\frac{\sqrt{2}}{3} \hat{i}+\frac{\sqrt{2}}{3} \hat{j}+\left(\frac{1}{2}+\frac{2 \sqrt{2}}{3}\right) \hat{k}\)
  2. B \(\frac{\sqrt{2}}{3} \hat{\mathrm{i}}+\frac{1}{3 \sqrt{2}} \hat{\mathrm{j}}-\frac{1}{2} \hat{\mathrm{k}}\)
  3. C \(\left(\frac{1}{\sqrt{3}}+\frac{1}{2}\right) \hat{i}+\left(\frac{1}{\sqrt{3}}-\frac{1}{3 \sqrt{2}}\right) \hat{j}+\left(\frac{1}{\sqrt{3}}+\frac{\sqrt{2}}{3}\right) \hat{k}\)
  4. D \(\frac{\sqrt{2}}{3} \mathrm{i}-\frac{1}{2} \hat{k}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{\sqrt{2}}{3} \mathrm{i}-\frac{1}{2} \hat{k}\)

Step-by-step Solution

Detailed explanation

\( \overrightarrow{\mathrm{C}}=\mathrm{C}_1 \hat{\mathrm{i}}+\mathrm{C}_2 \hat{\mathrm{j}}+\mathrm{C}_3 \hat{\mathrm{k}} \) \( \mathrm{C}_1^2+\mathrm{C}_2^2+\mathrm{C}_3{ }^2=1 \)…
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