JEE Mains · Maths · STD 12 - 10. vector algebra
Let a unit vector which makes an angle of \(60^{\circ}\) with \(2 \hat{i}+2 \hat{j}-\hat{k}\) and an angle of \(45^{\circ}\) with \(\hat{i}-\hat{k}\) be \(\overrightarrow{\mathrm{C}}\). Then \(\overrightarrow{\mathrm{C}}+\left(-\frac{1}{2} \hat{\mathrm{i}}+\frac{1}{3 \sqrt{2}} \hat{\mathrm{j}}-\frac{\sqrt{2}}{3} \hat{\mathrm{k}}\right)\) is :
- A \(-\frac{\sqrt{2}}{3} \hat{i}+\frac{\sqrt{2}}{3} \hat{j}+\left(\frac{1}{2}+\frac{2 \sqrt{2}}{3}\right) \hat{k}\)
- B \(\frac{\sqrt{2}}{3} \hat{\mathrm{i}}+\frac{1}{3 \sqrt{2}} \hat{\mathrm{j}}-\frac{1}{2} \hat{\mathrm{k}}\)
- C \(\left(\frac{1}{\sqrt{3}}+\frac{1}{2}\right) \hat{i}+\left(\frac{1}{\sqrt{3}}-\frac{1}{3 \sqrt{2}}\right) \hat{j}+\left(\frac{1}{\sqrt{3}}+\frac{\sqrt{2}}{3}\right) \hat{k}\)
- D \(\frac{\sqrt{2}}{3} \mathrm{i}-\frac{1}{2} \hat{k}\)
Answer & Solution
Correct Answer
(D) \(\frac{\sqrt{2}}{3} \mathrm{i}-\frac{1}{2} \hat{k}\)
Step-by-step Solution
Detailed explanation
\( \overrightarrow{\mathrm{C}}=\mathrm{C}_1 \hat{\mathrm{i}}+\mathrm{C}_2 \hat{\mathrm{j}}+\mathrm{C}_3 \hat{\mathrm{k}} \) \( \mathrm{C}_1^2+\mathrm{C}_2^2+\mathrm{C}_3{ }^2=1 \)…
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