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JEE Mains · Maths · STD 11 - 10.1 circle and system of circle

एक वृत्त के दो व्यासों के समीकरण \(2 x-3 y=5\) तथा \(3 x-4 y=7\) है। बिंदुओं \(\left(-\frac{22}{7},-4\right)\) तथा \(\left(-\frac{1}{7}, 3\right)\) को मिलाने वाली रेखा, वृत्त को केवल एक बिंदु \(\mathrm{P}(\alpha, \beta)\) पर मिलती है। तो \(17 \beta-\alpha\) = ...........

  1. A \(2\)
  2. B \(4\)
  3. C \(6\)
  4. D \(7\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(2\)

Step-by-step Solution

Detailed explanation

Centre of circle is \((1, -1)\) Equation of \(A B\) is \(7 x-3 y+10=0 \ldots\) \(....(i)\) Equation of \(\mathrm{CP}\) is \(3 x+7 y+4=0 \ldots\)\(......(ii)\) Solving \((i)\) and \((ii)\) \(\alpha=\frac{-41}{29}, \beta=\frac{1}{29} \quad \therefore 17 \beta-\alpha=2\)
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