ExamBro
ExamBro
JEE Mains · Maths · STD 12 - 13. probability

एक बक्से में \(15\) हरी तथा \(10\) पीली गेंदे है। यदि एक-एक करके यादृच्छया, प्रतिस्थापना सहित, \(10\) गेंदें निकाली जाएँ, तो हरी गेंदों की संख्या का प्रसरण है:

  1. A \(\frac{6}{{25}}\)
  2. B \(\frac{{12}}{5}\)
  3. C \(6\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{{12}}{5}\)

Step-by-step Solution

Detailed explanation

(2) We can apply binomial probability distribution We have \(n=10\) \(\mathrm{p}=\) Probability of drawing a green ball \(=\frac{15}{25}=\frac{3}{5}\) Also \(q=1-\frac{3}{5}=\frac{2}{5}\) Variance = npq \(=10 \times \frac{3}{5} \times \frac{2}{5}=\frac{12}{5}\)
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app