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JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry

\(A +2 B +3 C \rightleftharpoons AB _{2} C _{3}\) \(6.0\; g \;A , \;6.0 \times 10^{23}\) परमाणु \(B\) तथा \(0.036\) मोल \(C\) के अभिक्रिया करने पर \(4.8\; g \;AB _{2} C _{3}\) प्राप्त होता है। यदि \(A\) तथा \(C\) के परमाणु द्रव्यमान क्रमशः \(60\) और \(80 \;amu\) हों, तो \(B\) का परमाणु द्रव्यमान है। (आवोगाद्रो संख्या \(=6 \times 10^{23})\) 

  1. A \(50\)
  2. B \(60\)
  3. C \(70\)
  4. D \(40\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(50\)

Step-by-step Solution

Detailed explanation

\(A+3B+3C\rightleftharpoons A{{B}_{2}}{{C}_{3}}.....(1)\) No. of moles of \(A=\frac{6.0\,g}{60\,g/mol}=0.1\,mol\) No. of moles of \(B=\frac{6.00\times {{10}^{23}}}{6.000\times {{10}^{23}}}=1\,mol\) No. of moles of \(C = 0.036\) \(AB_2C_3\) formed accordingly to \(C\) which is a…
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