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JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry

\(61 \;g\) बेरियम क्लोराइड के हाइड्रेट के एक नमूने को गरम करके सुखाया गया। सूखे नमूने का वजन \(52\; g\) था। हाइड्रेट लवण का सूत्र है : (परमाणु द्रव्यमान, \(Ba =137\; amu , Cl =35.5 \;amu )\)

  1. A \(BaC{l_2}.4{H_2}O\)
  2. B \(BaC{l_2}.3{H_2}O\)
  3. C \(BaC{l_2}.{H_2}O\)
  4. D \(BaC{l_2}.2{H_2}O\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(BaC{l_2}.2{H_2}O\)

Step-by-step Solution

Detailed explanation

Weight of hydrated \(BaCl_2 = 61\,g\) Weight of anhydrous \(BaCl_2 = 52\,g\) Loss in mass \(= 9\,g\) Assuming \(BaCl_2.xH_2O\) as hydrate mass of \(H_2O = 9\,g\) Moles of \({{H}_{2}}O=\frac{9}{18}=0.5\) Grass molecular let of \(BaCl_2 = 208\) \(\%\) of \(H_2O\) in this hydrated…
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