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JEE Mains · Physics · STD 11 - 10.2 transmission of heat

એક પદાર્થ \(6\) મિનિટમાં \(60^{\circ} C\) થી \(40^{\circ} C\) સુધી ઠંડો પડે છે. જો પરિસરનું તાપમાન \(10^{\circ} C\) હોય, તો પછીની \(6\) મિનિટ પછી તેનું તાપમાન \(.........{ }^{\circ} C\) થશે.

  1. A \(28\)
  2. B \(22\)
  3. C \(20\)
  4. D \(21\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(28\)

Step-by-step Solution

Detailed explanation

By average form of Newton's law of cooling \(\frac{20}{6}= k (50-10)\) \(\frac{40- T }{6}= K \left(\frac{40+ T }{2}-10\right)\) From equation \((i)\) and \((ii)\) \(\frac{20}{40- T }=\frac{40}{10+ T / 2}\) \(10+\frac{ T }{2}=80-2\,T\)…
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