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JEE Mains · Maths · STD 11 - 7. binomial theoram

\((\mathrm{x}+\sqrt{\mathrm{x}^{2}-1})^{6}+(\mathrm{x}-\sqrt{\mathrm{x}^{2}-1})^{6}\) ના વિસ્તરણમાં  \(x^{4}\) અને \(x^{2}\) ના સહગુણકો \(\alpha\) અને \(\beta\) હોય તો  . . . .  

  1. A \(\alpha+\beta=60\)
  2. B \(\alpha+\beta=30\)
  3. C \(\alpha-\beta=-132\)
  4. D \(\alpha-\beta=60\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\alpha-\beta=-132\)

Step-by-step Solution

Detailed explanation

\(2\left[^{6} \mathrm{C}_{0} \mathrm{x}^{6}+^{6} \mathrm{C}_{2} \mathrm{x}^{4}\left(\mathrm{x}^{2}-1\right)+6 \mathrm{C}_{4} \mathrm{x}^{2}\left(\mathrm{x}^{2}-1\right)^{2}+^{6} \mathrm{C}_{6}\left(\mathrm{x}^{2}-1\right)^{3}\right]\) \(\alpha=-96 \;and\; \beta=36\)…
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