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JEE Mains · Maths · STD 11 - 12. limits

\(\mathop {\lim }\limits_{x \to 0} \frac{{x\,\tan \,2x - 2x\,\tan \,x}}{{{{\left( {1 - \cos \,2x} \right)}^2}}}\) = 

  1. A \(1\)
  2. B \( - \frac{1}{2}\)
  3. C \( \frac{1}{4}\)
  4. D \(  \frac{1}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(  \frac{1}{2}\)

Step-by-step Solution

Detailed explanation

Let, \(L = \,\,\,\mathop {\lim }\limits_{x \to 0} \frac{{\left( {x\tan 2x - 2x\tan \,x} \right)}}{{{{\left( {1 - \cos \,2x} \right)}^2}}} = \mathop {\lim }\limits_{x \to 0} K\) (say)…
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