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JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant

\((\alpha , \beta )\) ની કેટલી જોડ માટે સુરેખ સમીકરણો \(\left( {1 + \alpha } \right)x + \beta y + z = 2\) ; \(\alpha x + \left( {1 + \beta } \right)y + z = 3\) ; \(\alpha x  + \beta y + 2z = 2\) એ એકાકી ઉકેલ ધરાવે છે .

  1. A \((2, 4)\)
  2. B \((-3, 1)\)
  3. C \((-4, 2)\)
  4. D \((1, -3)\)
Verified Solution

Answer & Solution

Correct Answer

(A) \((2, 4)\)

Step-by-step Solution

Detailed explanation

\(\left( {1 + \alpha } \right)x + \beta y + z = 0\) \(\alpha x + \left( {1 + \beta } \right)y + z = 0\) \(\alpha x + \beta y + 2z = 0\) \(D = \left| {\begin{array}{*{20}{c}} {1 + \alpha }&\beta &1\\ \alpha &{1 + \beta }&1\\ \alpha &\beta &2 \end{array}} \right|\)…
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