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JEE Mains · Maths · STD 12 - 1. relation and function

વિધેય  \(f\left( x \right) = \left| {\sin \,4x} \right| + \left| {\cos \,2x} \right|\) નો આવર્તમાન મેળવો.

  1. A \(2 \pi \)
  2. B \(\pi \)
  3. C \(\frac{\pi}{2}\)
  4. D \(\frac{\pi}{4}\)
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Answer & Solution

Correct Answer

(C) \(\frac{\pi}{2}\)

Step-by-step Solution

Detailed explanation

\(\left| {\sin \,x} \right| + \left| {\cos \,x} \right|\) is periodic with oeriod \(\frac{\pi }{2}\). Hence, \(f\left( x \right) = \left| {\sin \,4x} \right| + \left| {\cos 2\,x} \right|\) is also periodic function with period \(\frac{\pi }{2}\)
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