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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

વિધેય \(f: R \rightarrow R,\) માટે \(f(0)=f(1)=f^{\prime}(0)=0\) હોય તો દ્વિતીય વિકલીનીય હોય તો 

  1. A કોઈક \(x \in(0,1)\) માટે \(f^{\prime \prime}(x)=0\)
  2. B \(f^{\prime \prime}(0)=0\)
  3. C દરેક \(x \in(0,1)\) માટે \(f^{\prime \prime}( x ) \neq 0\)
  4. D દરેક \(x \in(0,1)\) માટે \(f^{\prime \prime}(x)=0\)
Verified Solution

Answer & Solution

Correct Answer

(A) કોઈક \(x \in(0,1)\) માટે \(f^{\prime \prime}(x)=0\)

Step-by-step Solution

Detailed explanation

\(f(0)=f(1)=f^{\prime}(0)=0\) Apply Rolles theorem on \(y=f(x)\) in \(x \in[0,1]\) \(f(0)=f(1)=0\) \(\Rightarrow f^{\prime}(\alpha)=0\) where \(\alpha \in(0,1)\) Now apply Rolles theorem on \(y =f^{\prime}( x )\) \(\operatorname{in} x \in[0, \alpha]\)…
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